-19x^2+20x-12=0

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Solution for -19x^2+20x-12=0 equation: 



-19x^2+20x-12=0

a = -19; b = 20; c = -12;
Δ = b2-4ac
Δ = 202-4·(-19)·(-12)
Δ = -512
Delta is less than zero, so there is no solution for the equation

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